Question: When a polynomial $P(x)$ is divided by $(x+2)(x-4)$ the quotient is the polynomial $Q(x)$ and the remainder is $ax+b$. Find $a,b$ if $P(-2)=3$ and $P(4)=2$.
Solution.
Using the factor theorem we get two equations for $a,b$ which we can solve to find $a,b$.
We have $$P(x)=(x+2)(x-4)Q(x)+ax+b$$
Therefore
$P(-2)=3=-2a+b\implies -2a+b=3$ (1)
and
$P(4)=2=4a+b\implies 4a+b=2$ (2)
Subtract (2)-(2) gives
$-1=6a\implies a=-\dfrac{1}{6}$
Then $b=3+2(-1/6)=2\dfrac{2}{3}=8/3$.
Conclude: $$a=-\dfrac{1}{6}\:\ \mbox{ and }\:\ b=\dfrac{8}{3}$$.
Remember to check my working and tell me if I made an error!! (reward!)
